Trivial Trials Testing Total Capacity of Thought

Skill

the answer is 63, and it would take 7 weeks.

SMILEY

yourbuddy

skeptic wrote:

Aight - might be an easier way, but... After 7 weeks the king should have 63 nuxus.

The first week the king proposes that 33 citizens get a raise of 1 nuxu for a total of 2 each, and no one else including himself gets anything.
33 aye, 32 nay, 66 nuxus distributed.

The 2nd week the king proposes that 17 citizens get a raise of 1 nuxu for a total of 3 each, 16 citizens lose their pay, and the king gets 15.
17 aye, 16 nay, 66 nuxus distributed.

The 3rd week the king proposes that 9 citizens get a raise of 1 nuxu for a total of 4 each, 8 citizens lose their pay, and the king gets 30.
9 aye, 8 nay, 66 nuxus distributed.

The 4th week the king proposes that 5 citizens get a raise of 1 nuxu for a total of 5 each, 4 citizens lose their pay, and the king gets 41.
5 aye, 4 nay, 66 nuxus distributed.

The 5th week the king proposes that 3 citizens get a raise of 1 nuxu for a total of 6 each, 2 citizens lose their pay, and the king gets 48.
3 aye, 2 nay, 66 nuxus distributed.

The 6th week the king proposes that 2 citizens get a raise of 1 nuxu for a total of 7 each, 1 citizen loses pay, and the king gets 52.
2 aye, 1 nay, 66 nuxus distributed.

The 7th week the king proposes that 3 citizens, who are without any pay, get a raise of 1 nuxu each. And that the two citizens earning 7 nuxus lose their pay entirely. And the king gets 63.
3 aye, 2 nay, 66 nuxus distributed.

Correct

yourbuddy

Fingulfin has a pendent with 9 red frags arrayed as so:

                                                       1               2               3
                                                  Object        Object    Patch

                                                       4               5               6
                                                   Object       Object       Object
                                                       7               8               9
                                                   Object       Object       Object

Fingulfin has a friend named Stot who has Coder tree still in its beta testing(OMFGWTFH4X). In this tree, there is an ablity named "alteration', and this ability allows Objects to turn into Patches, Patches to turn into Subroutines, and Subroutines into Objects. The problem is, there are still some bugs to be worked out with this ability. Instead of just changing one Red Frag, it changes all frags touching it. IE, if Stot used his ability on the frag in slot 6, the frags 5,6,9 would become patches, while the frag in slot 3 would become a subroutine!!! Stot wants to be able to stack all of his red frags together, so all of them have to be the same. What is the fewest times Stot has to use "Alteration"? And briefly explain how you dd it.

Kivo

Well he could just stack them all as objects and use no alterations. SMILEY

Kivo

Um...nvm. I didn't see the patch there. Now I feel stupid. SMILEY

SMILEY

skeptic

Stot needs 5 alterations to stack 9 Subs

1st alteration to slot 9 changes 6, 8, 9 to Patches

2nd alteration to slot 4 changes 1, 4, 5, 7 to Patches

3rd alteration to slot 3 changes 2 to Patch & 3, 6 to Subroutines

4th alteration to slot 8 changes 5, 7, 8, 9 to Subroutines

5th alteration to slot 1 changes 1, 2, 4 to Subroutines

yourbuddy

skeptic wrote:

Stot needs 5 alterations to stack 9 Subs

1st alteration to slot 9 changes 6, 8, 9 to Patches

2nd alteration to slot 4 changes 1, 4, 5, 7 to Patches

3rd alteration to slot 3 changes 2 to Patch & 3, 6 to Subroutines

4th alteration to slot 8 changes 5, 7, 8, 9 to Subroutines

5th alteration to slot 1 changes 1, 2, 4 to Subroutines

Correct. Also, another 500k for the next person to post an alternate way of doing this.

skeptic

You can rearrange the order of the changes but I haven't yet found a combination that doesn't use only slots 1, 3, 4, 8, & 9.

yourbuddy

skeptic wrote:

You can rearrange the order of the changes but I haven't yet found a combination that doesn't use only slots 1, 3, 4, 8, & 9.

This is all I wanted. I just wanted people test and try and just realize they can rearrange the order and it can still work. Not in an order though, are 5 arrangements of 1.3.4.8.9 that can work. You get 500k

skeptic

lol - this has been fun.

I don't want to hijack your thread but I'll pass your $500,000 along & add $1,000,000 to the first person to correctly narrate the solution to the 3 Black Hats, 2 White Hats riddle. No diagrams or charts - you must be the first poster to correctly reply with a narrative description of the solution. If no one can answer this I will post the text of the riddle in approximately 24 hours.

Keep up the good work, Fin SMILEY

yourbuddy

I know the answer, but I won't post it yet. Since I check this thread more than anyone else does I am probably the first to look at your partake. I might be down for a few days, as I have to make some more problems. Probably only until the end of this week. Would be tomorrow, but classes just started again. I'll check later tonight and see if anyone has posted. And also, the 1.5 mil you are sending came from me most likely SMILEY

skeptic

First off - I like the Forehead Mark version better than the Hat version cause some wisenheimer always says that he can look up and see the color of a hat. But the riddle is commonly known as 3 Black Hats, 2 White Hats or maybe vice versa.

Three men compete. Each is given a single mark on the forehead. The marks are made with charcoal strips drawn from a lot of five. Three strips are black and two strips are white. The men will answer in order. The winner is the first to correctly state the color of his mark. Any man who guesses will be immediately zerged. The first man says he cannot state the color of his mark. The second man says he cannot state the color of his mark. The third man says he knows the color of his mark.

What is the color of the third man's mark, and how does he know?

yourbuddy

skeptic wrote:

First off - I like the Forehead Mark version better than the Hat version cause some wisenheimer always says that he can look up and see the color of a hat. But the riddle is commonly known as 3 Black Hats, 2 White Hats or maybe vice versa.

Three men compete. Each is given a single mark on the forehead. The marks are made with charcoal strips drawn from a lot of five. Three strips are black and two strips are white. The men will answer in order. The winner is the first to correctly state the color of his mark. Any man who guesses will be immediately zerged. The first man says he cannot state the color of his mark. The second man says he cannot state the color of his mark. The third man says he knows the color of his mark.

What is the color of the third man's mark, and how does he know?

In this, the third person cannot see either of the two correct? And the second person can only see the third person correct? Just want to make sure we are doing the same riddle.

skeptic

I'm presuming ceterus paribus, that the men have the same knowledge & can see each other.

skeptic

Frell, no edit. Should be ceteris. Sorry.